1.

Integrate the following functions: tan^3 2x sec(2x)

Answer»

Solution :`tan^3 2x sec 2x = tan^2 2x sec 2x tan 2x`
= (sec^2 2x-1) sec 2x tan 2x`
PUT t = sec 2x
Then DT = 2 sec 2x tan 2x dx
`gt sec 2x tan 2x = dt/2
THEREFORE `int tan^3 2x sex 2x dx = `int (t^2-1) dt/2`
=1/2[t^3/3-t]+C`
=`1/2[(sec^3 2x)/3 - sec2x]+c`


Discussion

No Comment Found

Related InterviewSolutions