Saved Bookmarks
| 1. |
Integrate the following functions: tan^3 2x sec(2x) |
|
Answer» Solution :`tan^3 2x sec 2x = tan^2 2x sec 2x tan 2x` = (sec^2 2x-1) sec 2x tan 2x` PUT t = sec 2x Then DT = 2 sec 2x tan 2x dx `gt sec 2x tan 2x = dt/2 THEREFORE `int tan^3 2x sex 2x dx = `int (t^2-1) dt/2` =1/2[t^3/3-t]+C` =`1/2[(sec^3 2x)/3 - sec2x]+c` |
|