1.

Integrate the following functions: tan^4x

Answer»

Solution :`tan^4x = tan^2 X tan^2 x`
=`tan^2 x sec^2 x-(sec^2 x-1)`
=`tan^2 x sec^2 x -sec^2 x+1`
THEREFORE `INT tan^4 x dx`
=`int (ta_n^2x sec^2 x-sec^2 x+1)dx`
`int t^2dt-TANX+x+c`, if we PUT
tanx =t
=`t^3/3-tanx+x+c`
=`tan^3 x/3 -tanx+x+c`


Discussion

No Comment Found

Related InterviewSolutions