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Integrate the following functions w.r.t.x cosx/sqrt(4-sin^2x)

Answer»

SOLUTION :Put t = SINX. Then dt = cosx DX
therefore `INT cosx/sqrt(4-sin^2x) dx = int (dt)/sqrt(4-t^2)`
=`int dt/sqrt(2^2 -t^2) = sin^-1(t/2) +c`
=`sin^-1(sinx/2) +c`


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