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Integrate the following functions ((x+1)(x+logx)^2)/x |
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Answer» Solution :`((x+1)(x+logx)^2)/x` `(1+1/x)(x+logx)^2` LET t = x+logx. Then DT = (1+1/x)DX therefore `int ((x+1)(x+logx)^2)/x dx = int t^2 dt` `t^3/3 +C = (x+logx)^3/3 +c` |
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