1.

Integrate the following functions ((x+1)(x+logx)^2)/x

Answer»

Solution :`((x+1)(x+logx)^2)/x`
`(1+1/x)(x+logx)^2`
LET t = x+logx.
Then DT = (1+1/x)DX
therefore `int ((x+1)(x+logx)^2)/x dx = int t^2 dt`
`t^3/3 +C = (x+logx)^3/3 +c`


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