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Integrate the following functions x^2/(1-x^6) |
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Answer» SOLUTION :LET t = `x^3`. Then DT = `3x^2 dx` `gt x^2 dx = 1/3 dt` therefore` int x^2/(1-x^6) dx = int x^2/(1-(x^2)^3) dx` = `int 1/(1-t^2) 1/3 dt` =`1/3 xx 1/2 log |(1+t)/(1-t)|+C` =`1/6 log|(1+x^3)/(1-x^3)|+c` |
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