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Integrate the following functions x^2/(2+3x^3)^3 |
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Answer» Solution :Let t = `2+3x^3`, Then DT = `9x^2 DX gt x^2 dx = 1/9 dt` therefore `int x^2/(2+3x^3)^3 dx = int 1/t^3 1/9 dt` =`1/9 int r^(-3) dt = 1/9 xx t^(-3+1)/(-3+1) +c` `1/(-18) t^(-2) +c = -1/(18t^2) +c` =`-1/(18(2+3x^3)^2 +c`. |
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