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Integrate the following int(dx)/(3x^2+7) |
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Answer» Solution :`int(dx)/(3x^2+7)` [PUT `x= sqrt(7/3) TAN THETA` then `dx=sqrt(7/3)sec^2theta d theta` `(1/3)int(dx)/(x^2+(7/3))=1/3 sqrt(7/3)/(7/3)int(sec^2theta d theta)/(sec^2theta)` (1/sqrt21)tan^(-1)((sqrt3x)/SQRT7) +C` |
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