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Integrate the following int((sec^(-1)x)^2dx)/(xsqrt(x^2-1) |
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Answer» Solution :`INT((sec^(-1)x)^2dx)/(xsqrt(x^2-1)` [PUT`sec^(-1)x=t then `DX/(xsqrt(x^2-1))=DT` `intt^2dt` `(/3)t^3+C=(1/3)(sec^(-1)x)^3+C` |
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