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Integrate the following int(sectheta tantheta)/(sec^2theta+4) d theta |
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Answer» Solution :`INT(sectheta TANTHETA)/(sec^2theta+4) d theta` [put `sectheta=t` then `sectheta CDOT tantheta d theta =dt` `int(dt)/(4+t^2)`=`int(dt)/(2^2+t^2)=(1/2)tan^(-1)(t/2)+C` `(1/2)tan^(-1)(sectheta/2)+C` |
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