1.

Integrate the following int(sectheta tantheta)/(sec^2theta+4) d theta

Answer»

Solution :`INT(sectheta TANTHETA)/(sec^2theta+4) d theta`
[put `sectheta=t` then `sectheta CDOT tantheta d theta =dt`
`int(dt)/(4+t^2)`=`int(dt)/(2^2+t^2)=(1/2)tan^(-1)(t/2)+C`
`(1/2)tan^(-1)(sectheta/2)+C`


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