1.

Integrate the following int(sinx)/(cos^3x)dx

Answer»

Solution :`INT(SINX)/(cos^3x) DX`
[PUT cosx=t then sinx dx=-dt]
`int((-dt)/t^3)=-int-t^3 dt`
`-t^(-2)/-2+C=(1/2t^2)+C.


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