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Integrate the following : int(sqrtx+2)^2/x^4dx

Answer»

SOLUTION :`INT(sqrtx+2)^2/(x^4)DX`
=`int(x+4+2xx(2sqrtx))/(x^4)dx`
=`int(x^-3+4x^-4+4x^(-7/2))dx`
=`x^-2/-2+4(x^-3)/-3+4x^(-5/2)/(-5/2)+C`
=`-1/2xx1/(x^2)-4/3xx1/(x^3)-8/5xx1/x^(5/2)+C`


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