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Integrate the following int(x)/(sqrt(x^2-a^2)dx |
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Answer» Solution :`INT(X)/sqrt(x^2-a^2)dx [ put `x^2-a^2=t^2` then 2xdx=2tdt or xdx=tdt] `int(tdt)/t=intdt=t+C `sqrt(x^2-a^2)+C` |
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