1.

Integrate the following int(x)/(sqrt(x^2-a^2)dx

Answer»

Solution :`INT(X)/sqrt(x^2-a^2)dx
[ put `x^2-a^2=t^2` then 2xdx=2tdt or xdx=tdt]
`int(tdt)/t=intdt=t+C
`sqrt(x^2-a^2)+C`


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