1.

Integrate the follwing functions: 1/(x^2-9)

Answer»

SOLUTION :`1/(x^2-9) = 1/((x-3)(x=3))`
`= 1/6[1/(x-3) - 1/(x+3)]`
`GT INT 1/(x^2-9) dx`
=`1/6 [LOG|x-3|-log|x+3|]+c`
=1/6 log |(x-3)/(x+3)| +c`


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