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Integrate the follwing functions: 1/(x^2-9) |
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Answer» SOLUTION :`1/(x^2-9) = 1/((x-3)(x=3))` `= 1/6[1/(x-3) - 1/(x+3)]` `GT INT 1/(x^2-9) dx` =`1/6 [LOG|x-3|-log|x+3|]+c` =1/6 log |(x-3)/(x+3)| +c` |
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