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Integrate the follwing functions: 1/(x^4-1) |
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Answer» Solution :`1/(x^4-1) = 1/((x^2-1)(x^2+1))` =`1/2[1/(x^2-1) -1/(x^+1)]` `INT 1/(x^4-1) DX` =`1/2[INT1/(x^2-1) dx -int 1/(x^2+1) dx]` =`1/4 LOG|(x-1)/(x+1)| -1/2 tan^-1x +C` |
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