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Integrate the follwing functions: (2x)/(x^2+3x+2) |
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Answer» Solution :Let `(2X)/(X^2+3x+2) = (2x)/((x+1)(x+2)) = A/(x+1) + B/(x+2)` Then 2x = A(x+2)+b(x+1)....(a) Putting x = -1 and x = -2 in (a) we have -2 = `Axx1 gtA = -2`, -4 = `Bxx-1 gt B = 4` THEREFORE `int (2x)/(x^2+3x+2) dx` = `-2log|x+1|+4 log|x+2|+c` |
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