 
                 
                InterviewSolution
 Saved Bookmarks
    				| 1. | Integrate the follwing functions: cosx/((1-sinx)(2-sinx)) | 
| Answer» Solution :Put SINX = t. Then dt = COSX dx THEREFORE `INT cosx/((1-sinx)(2-sinx)) dx` `int dt/((1-t)(2-t))` (by partial fraction) =`int[1/(1-t)-1/(2-t)]dt` `LOG|1-t|/-1 -log|2-t|/-1 +c` =`log|2-t|-log|1-t|+c` =`log|(2-t)/(1-t)|+c` =`log|(2-sinx)/(1-sinx)|+c` | |