1.

Integrate : ∫x2ex dx

Answer»

Let I = ∫x2ex dx

= x2∫ex dx - ∫{(dx2/dx) ∫x2ex} dx

= x2ex - ∫2x ex dx

= x2ex - 2∫xex dx

= x2ex - 2[x∫ex dx -  ∫(dx/dx) x (ex) dx

= x2ex - 2[xex - ∫ex] dx

= x2ex - 2[xex - ex] +  c

= x2ex - 2xex - ex + c



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