Saved Bookmarks
| 1. |
Integrate : ∫x2ex dx |
|
Answer» Let I = ∫x2ex dx = x2∫ex dx - ∫{(dx2/dx) ∫x2ex} dx = x2ex - ∫2x ex dx = x2ex - 2∫xex dx = x2ex - 2[x∫ex dx - ∫(dx/dx) x (ex) dx = x2ex - 2[xex - ∫ex] dx = x2ex - 2[xex - ex] + c = x2ex - 2xex - ex + c |
|