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Integration of 3rd equation of motion

Answer» 3rd motion : 2as=v^2-u^2S=1/2(v+u)tS=(v+u÷2)tS=v\'tNow expand v\'tV\'t=[v+u÷2][v-u÷a]. [t=v-u÷2]nowV\'t=v+u/2×v-u/aThen V^2-u^2=2asThus we derived the third equation of motion


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