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Interference fringes are obtained due to the interference of wave from two coherent sources of light with amplitudes `a_(1)` and `a_(2)(a_(1)=2a_(2))`. The ratio of the maximum and minimum intensities of light in the interference pattern isA. `2:1`B. `4:9`C. `9:1`D. `9:4` |
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Answer» Correct Answer - C `(I_("max"))/(I_("min"))=((a_(1)+a_(2))^(2))/((a_(1)-a_(2))^(2))=((2a_(2)+a_(2))^(2))/((2a_(2)-a_(2)))=(9)/(1)` |
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