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Intergrate the following: intcos5x cos2xdx |
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Answer» SOLUTION :`intcos5x COS2XDX` =`1/2 int2cos5x cos2xdx` =`1/2 `INT(cos7x+cos3x)DX` 1/2.1/7sin7x+1/2.1/3sin3x+C =1/14sin7x+1/6sin3x+C |
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