1.

Intergrate the following: intcos5x cos2xdx

Answer»

SOLUTION :`intcos5x COS2XDX`
=`1/2 int2cos5x cos2xdx`
=`1/2 `INT(cos7x+cos3x)DX`
1/2.1/7sin7x+1/2.1/3sin3x+C
=1/14sin7x+1/6sin3x+C


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