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Intergrate the following: intsin4x cos3xdx |
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Answer» SOLUTION :`intsin4x cos3xdx` =`1/2 int2sin4x .cos3xdx` =`1/2int(sin7x+sinx)DX` =`1/2{-(COS7X)/7-cosx}+C` =-1/14cos7x-1/2 cosx+C |
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