1.

Intergrate the following: intsin4x cos3xdx

Answer»

SOLUTION :`intsin4x cos3xdx`
=`1/2 int2sin4x .cos3xdx`
=`1/2int(sin7x+sinx)DX`
=`1/2{-(COS7X)/7-cosx}+C`
=-1/14cos7x-1/2 cosx+C


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