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InterviewSolution
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INTEXT QUESTIONS 7.21. Name the two types of ions present in NaCl.2. How many shells are present in Nation?3 What is the number of electrons present in C ion? |
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Answer» ans 1. NaCl(s) = Na+(aq) + Cl-(aq) Since NaCl is an ionic solid (s), which consists of cations Na+ and anions Cl-. 2. Sodium(Na) is an atom consisting of 11 electrons. When sodium gives away 1 electron to attain stability, it becomes a positive ion i.e. it has more number of protons than electrons this is denoted by Na+. Electronic Configuration of Sodium is 1s2 2s2 2p6 3s1 When it gives away one electron it is given away from the s-shell of the 3rd orbit. After formation of Sodium ion(Na+), the configuration becomes 1s2 2s2 2p6. Thus Sodium ion (Na+) has 3 shells i.e. 1s, 2s and 2p. 3. The chloride ion,Cl−, has a charge of−1, meaning, it had gained 1 electron in its outermost orbital. The overall number of electrons is now18. Thus, the electron configuration forCl−should be 1s22s22p63s23p6=18 electrons |
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