1.

intsin^20xcos^3xdx

Answer»

SOLUTION :`intsin^20xcos^3xdx`
=`intsin^20x.(1-sin^2x)cosxdx`
[PUT sinx=t
Then cosxdx=DT]
=`intt^20(1-t^2)dt=int(t^20-t^22)dt`
=`1/21t^21-1/23t^23+C`
=`1/21sin^21x-1/23sin^23x+C`


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