InterviewSolution
Saved Bookmarks
| 1. |
intsin^20xcos^3xdx |
|
Answer» SOLUTION :`intsin^20xcos^3xdx` =`intsin^20x.(1-sin^2x)cosxdx` [PUT sinx=t Then cosxdx=DT] =`intt^20(1-t^2)dt=int(t^20-t^22)dt` =`1/21t^21-1/23t^23+C` =`1/21sin^21x-1/23sin^23x+C` |
|