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intsin^3xdx |
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Answer» SOLUTION :`intsin^3xdx=intsin^2x.sinxdx` =`INT(1-cos^2x)sinxdx` [PUT cox=t Then sinxdx=-DT] =`int(1-t^2).(-dt)=1/3t^3-t+C` `1/3cos^3x-cosx+C` |
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