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intsin^3xsec^14xdx |
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Answer» SOLUTION :`intsin^3xsec^14xdx` =`intsin^3x/cos^14x dx` =`int((1-cos^2x)sinx)/cos^14x dx` [PUT cosx=t Then sinxdx=-DT] =`int(t^2-1)/t^14 dt=int(t^-12-t^-14)dt` =`-1/11t^-11+1/13t^-13+C` =`1/13sec^13x-1/11sec^11x+C` |
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