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intsin3xcos^2xdx |
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Answer» SOLUTION :`intsin3xcos^2xdx` =`intsin3x.(1+cos2x)/2dx` =`1/2 INT{sin3x+sin3x.cos2xdx}` =`1/2intsin3x+1/4 int2.sin3x.cos2x.DX` =-1/6cos3x+`1/4 int(sin5x+sinx)dx` =-1/6cos3x-1/20cos5x-1/4cosx+C |
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