`intsqrt(1+sin((x)/(4)))dx` is equal toA. `B(sin.(x)/(8)-cos.(x)/(8))+c`B. `(sin.(x)/(8)+cos.(x)/(8))+c`C. `(1)/(8)(sin.(x)/(8)-cos.(x)/(8))+c`D. `8(cos.(x)/(8)-sin.(x)/(8))+c`

`intsqrt(1+sin((x)/(4)))dx` is equal toA. `B(sin.(x)/(8)-cos.(x)/(8))+

1.	`intsqrt(1+sin((x)/(4)))dx` is equal toA. `B(sin.(x)/(8)-cos.(x)/(8))+c`B. `(sin.(x)/(8)+cos.(x)/(8))+c`C. `(1)/(8)(sin.(x)/(8)-cos.(x)/(8))+c`D. `8(cos.(x)/(8)-sin.(x)/(8))+c`
Answer» Correct Answer - A We know that , `sqrt(1+sin2theta)=sintheta+costheta` `intsqrt(1+sin.(x)/(4))dx` `=int(sin.(x)/(8) +cos.(x)/(8))dx` `=-8cos.(x)/(8)+8sin.(x)/(8)+c` `=8(sin.(x)/(8)-cos.(x)/(8))+c`

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`intsqrt(1+sin((x)/(4)))dx` is equal toA. `B(sin.(x)/(8)-cos.(x)/(8))+c`B. `(sin.(x)/(8)+cos.(x)/(8))+c`C. `(1)/(8)(sin.(x)/(8)-cos.(x)/(8))+c`D. `8(cos.(x)/(8)-sin.(x)/(8))+c`

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