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`intsqrt(4x^(2)+9)dx` का मान ज्ञात कीजिए ।

Answer» `int sqrt(4x^(2)+9)dx" माना "2x=t`
`=intsqrt((2x)^(2)+3^(2))dx" "thereofore 2=(dt)/(dx)`
`=intsqrt(t^(2)+3^(2)).(dt)/(2)" "rArr" "dx=(dt)/(2)`
`=(1)/(2)[(t)/(2)sqrt(t^(2)+3^(2))+(3^(2))/(2)log|t+sqrt(t^(2)+3^(2))|]+c`
`=(1)/(4)[2xsqrt(4x^(2)+9)+9log |2x+sqrt(4x^(2)+9)|]+c`


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