1.

intsqrt(x^2-6x+5)dx

Answer»

SOLUTION :`intsqrt(x^2-6x+5)DX=intsqrt((x-3)^2-2^2) dx`
=`(x-3)/2sqrt((x-3)^2-2^2)-2^2/2In(x-3+SQRT((x-3)^2-2^2)+C)`
=`[becauseintsqrt(x^2-a^2)dx
=x/2sqrt(x^2-a^2)-a^2/2In(x+sqrt(x^2-a^2))]`
=`1/2(x-3)sqrt(x^2-6x+5)-2In(x-3+sqrt(x^2-6x+5))+C`


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