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intsqrt(x^2-6x+5)dx |
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Answer» SOLUTION :`intsqrt(x^2-6x+5)DX=intsqrt((x-3)^2-2^2) dx` =`(x-3)/2sqrt((x-3)^2-2^2)-2^2/2In(x-3+SQRT((x-3)^2-2^2)+C)` =`[becauseintsqrt(x^2-a^2)dx =x/2sqrt(x^2-a^2)-a^2/2In(x+sqrt(x^2-a^2))]` =`1/2(x-3)sqrt(x^2-6x+5)-2In(x-3+sqrt(x^2-6x+5))+C` |
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