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inttan^5theta sec^4theta d theta |
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Answer» SOLUTION :`inttan^5theta sec^4theta d THETA` =`inttan^5theta.(1+tan^2theta).sec^2thetad theta` [PUT `tantheta=1` Then `sec^2thetad theta=DT`] =`intt^5.(1+t^2).dt=int(t^5+t^7)dt` =`1/6t^6+1/8t^8+C=1/6tan^6theta+1/8tan^8theta+C` |
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