1.

intx cosec x Cotx dx =

Answer»

xcosecx - log `| TAN ""(x)/(2)| + c`
`-`xcosecx + log `| tan ""(x)/(2)| + c`
xcosecx - 2LOG `| tan ""(x)/(2)| + c`
xCotx + log `|tan ""(x)/(2)|+ c`

ANSWER :B


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