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intxcos^2xdx |
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Answer» SOLUTION :`intxcos^2xdx=intx.(1+cos2x)/2 DX` =`1/2intxdx+1/2intx.cos2xdx` =`1/4x^2+1/2{X.(SIN2X)/2-1/4int(sin2x)/2dx}` =`1/4x^2+1/4xsin2x-1/4intsin2xdx` =`1/4x^2+1/4xsin2x+1/8cos2x+C` |
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