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Iodate oxidises chromic hydroxide and gives iodide and chromate in basic medium. |
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Answer» Solution :(a) The ionic SKELETON equation is written as `IO_(3)^(-) +Cr(OH)_(3) OVERSET(OH^(-))to I^(-)+CrO_(4)^(2-)` (b) Writing oxidation numbers `overset(+5)(I) overset(-2)(O_(3)^(-)) +overset(+3)(Cr) overset(-2 +1)(OH_(3)) to overset(-1)(I^(-))+overset(+6)(Cr) overset(-2) (O_(4)^(-2))` (c) Locating atoms undergoing change in oxidation numbers. `overset(+5)(IO_(3)^(-)) +overset(+3)(Cr(OH)_(3)) to overset(-1) (I^(-)) +overset(+6)(Cr) O_(4)^(-2)` (d) Dividing the reaction into two halves and balancing in ACIDIC medium, separately. (e) Equalising the ELEMENTS and adding the two halves `eq (a) xx 2+eq (b) xx 1," we get"` `2Cr(OH)_(3)+10OH^(-) to 6e^(-)+2CrO_(4)^(2-)+8H_(2)O` `IO_(3)^(-)+6H_(2)O+6e^(-) to I^(-)+6OH^(-)` `IO_(3)^(-)+2Cr(OH)_(3)+4OH^(-) to I^(-)+2CrO_(4)^(2-)+5H_(2)O` This is the balanced equation. |
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