1.

Iodine is liberated from sodium iodate by reacting withA. dil. `H_2SO_4`B. `KMnO_4`C. `NaHSO_3`D. HCl

Answer» Correct Answer - C
This can be done with conc. `H_2SO_4 or NaHSO_3`
`2 NaIO_3 + 5 NaHSO_3 to 3NaHSO_4 + 2 Na_2SO_4+I_2+ H_2O`


Discussion

No Comment Found

Related InterviewSolutions