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Iodine is liberated from sodium iodate by reacting withA. dil. `H_2SO_4`B. `KMnO_4`C. `NaHSO_3`D. HCl |
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Answer» Correct Answer - C This can be done with conc. `H_2SO_4 or NaHSO_3` `2 NaIO_3 + 5 NaHSO_3 to 3NaHSO_4 + 2 Na_2SO_4+I_2+ H_2O` |
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