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iodine oxidises the `S_2O_3^(2-)` ion toA. `SO_3^(2-)`B. `SO_4^(2-)`C. `S_4O_6^(2-)`D. `S^(2-)` |
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Answer» Correct Answer - C `I_2+S_2O_3^(2-)tounderset("Tetrathionate ion")(S_4O_6^(2-)) +2I^(-)` |
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