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Ionisation constant of a weak acid (HA) in terms of `A_(m)^(oo)` and `A_(m)` is:A. `K_a=(CLambda_m^oo)/(Lambda_m-Lambda^oo)`B. `K_a=(CLambda_m^2)/(Lambda_m^oo(Lambda_m^oo-Lambda_m)`C. `K_a=(CLambda(Lambda_m^oo)^2)/(Lambda_m^oo(Lambda_m^oo-Lambda_m)`D. None of these |
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Answer» Correct Answer - B |
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