Ionisation constant of a weak base MOH, is given by the expression K_b=([M^+][OH^-])/([MOH]) Values of ionisation constant of some weak bases at a particular temperature are given below: {:("Base","Dimethylamine","Urea","Pyridine","Ammonia"),(K_b,5.4xx10^(-4),1.3xx10^(-14),1.77xx10^(-9),1.77xx10^(-5)):} Arrange the bases in decreasing order of the extent of their ionisation at equilibrium. Which of the above base is the strongest ?

Ionisation constant of a weak base MOH, is given by the expression K_

1.	Ionisation constant of a weak base MOH, is given by the expression K_b=([M^+][OH^-])/([MOH]) Values of ionisation constant of some weak bases at a particular temperature are given below: {:("Base","Dimethylamine","Urea","Pyridine","Ammonia"),(K_b,5.4xx10^(-4),1.3xx10^(-14),1.77xx10^(-9),1.77xx10^(-5)):} Arrange the bases in decreasing order of the extent of their ionisation at equilibrium. Which of the above base is the strongest ?
Answer» Solution :lonisation CONSTANT of a weak base MOH `K_b=[M^+][OH^-][MOH]` More the IONISATION constant `(K_b)` of a base, more is its ionisation and stronger the base. So, dimethyl amine is the STRONGEST base. `{:(K_b,"Dimethylamine",gt,"Ammonia",gt , "Pyridine",gt,"Urea"),(,5.4xx10^(-4),,1.77xx10^(-5),,1.77xx10^(-9),,1.3xx10^(-14)):}`