Ionisation constant of a weak base MOH, is given by the expression K_(b) = ([M^(+)][OH^(-)])/([MOH]) Values of ionisation constantof some weak bases at a particular temperature are given below : {:("Base","Dimethylamine","Urea","Pyridine","Ammonia",,,),(K_(b),5.4xx10^(-4),1.3xx10^(-14),1.77xx10^(-9),1.77xx10^(-5),,,):} Arrange the bases in decreasing order of the extent of their ionisation at equilibrium. Which of the above base is the strongest ?

Ionisation constant of a weak base MOH, is given by the expression K_(

1.	Ionisation constant of a weak base MOH, is given by the expression K_(b) = ([M^(+)][OH^(-)])/([MOH]) Values of ionisation constantof some weak bases at a particular temperature are given below : {:("Base","Dimethylamine","Urea","Pyridine","Ammonia",,,),(K_(b),5.4xx10^(-4),1.3xx10^(-14),1.77xx10^(-9),1.77xx10^(-5),,,):} Arrange the bases in decreasing order of the extent of their ionisation at equilibrium. Which of the above base is the strongest ?
Answer» Solution :Greater the ionizationconstant `(K_(b))` of a BASE, greater is the ionization of the base. HENCE, order of ionization will be `{:(,"DIMETHYLAMINE",gt,"Ammonia",gt,"Pyridine",gt,"Urea",),(K_(b),5.4xx10^(-4),,1.77xx10^(-5),,1.77xx10^(-9),,1.3xx10^(-14),):}`