1.

Ionisation constant of CH_(3)CO O His 1.7xx10^(-5) and concentration of H^(+) ions is 3.4 xx 10^(-4). Then initial concentration of CH_(3) C O O H molecules is

Answer»

`3.4xx10^(-4)`
`3.4xx10^(-3)`
`6.8xx10^(-3)`
`1.7xx10^(-3)`

Solution :`{:(,XH_(3)CO OH" " hArr" " CH_(3)CO O^(-) + H^(+)),("Initial conc.",""a),("At. eqm.",(a-3.4 xx 10^(-4)) " "3.4xx10^(-4)" " 3.4 xx 10^(-4)):}`
`((3.4xx10^(-4))(3.4xx10^(-4)))/((a-3.4 xx 10^(-4))) = 1.7 xx 10^(-5) ` (Given)
or, `(a-3.4xx10^(4))=((3.4xx10^(-4))^(2))/(1.7xx10^(-5))=6.8xx10^(-3)`
or `a=6.8xx10^(-3)+3.4xx10^(-4)~~ 6.8 xx 10^(-3)`


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