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Ionisation constant of CH_(3)CO O His 1.7xx10^(-5) and concentration of H^(+) ions is 3.4 xx 10^(-4). Then initial concentration of CH_(3) C O O H molecules is |
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Answer» `3.4xx10^(-4)` `((3.4xx10^(-4))(3.4xx10^(-4)))/((a-3.4 xx 10^(-4))) = 1.7 xx 10^(-5) ` (Given) or, `(a-3.4xx10^(4))=((3.4xx10^(-4))^(2))/(1.7xx10^(-5))=6.8xx10^(-3)` or `a=6.8xx10^(-3)+3.4xx10^(-4)~~ 6.8 xx 10^(-3)` |
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