1.

Ionisation energy of He^(+) is 19.6 xx 10^(-18)"J atom"^(-1) The energy of the first stationary state of Li^(2+) is

Answer»

`-4.41 xx 10^(-18) J ."atom"^(-1)`
`-4.41 xx 10^(-17) J ."atom"^(-1)`
`-4.41 xx 10^(-16) J ."atom"^(-1)`
`8.72 xx 10^(-18)J ."atom"^(-1)`

SOLUTION :`(E_1)/(E_2) = (Z_1^2)/(Z_2^2) xx (n_2^2)/(n_1^2)`


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