ionisationenergyof Heis19.6 xx 10^(-18)j atom^(-1 )Theenergyof the firststationarystate(n=1)of Li^(+) is

ionisationenergyof Heis19.6 xx 10^(-18)j atom^(-1 )Theenergyof the fir

1.	ionisationenergyof Heis19.6 xx 10^(-18)j atom^(-1 )Theenergyof the firststationarystate(n=1)of Li^(+) is
Answer» `4.14 xx 10^(16)atom^(-1)` `4.14xx 10^(17) J ` atom `2.2xx 10^(15)J ` atom `8.82 xx 10^(17) J` atom Solution :ionisationenergyfor `He^(+)` `E_(1)(He^(+))= -0 19.6 xx10^(18) J atom^(-1)` where `E_(n) =`ionizationenergyof `He^(+)` K = theenergyof the firststationary state `Z=2 ` `k=(-19.6 xx 10^(18))/(4 )= 4.9xx 10^(18)` `E_(1) (L_(1)%^(2))= (4.9 xx 10^(18)3^(2))/( 1^(2))` `44.1xx 10^(18)` `4.41 xx 10^(17J atom^(1)`