1.

Iri the circuit shown in figure-3.334, the resistance of voltmeter is` 6kOmega`. The voltmeter reading will be : A. `6V`B. `5V`C. `4V`D. `3V`

Answer» Correct Answer - B
Net resistance of `3kOmega` and voltmeter is also `2kOmega`. Now, the applied `10 V` is equally distributed between `2Omega and 2kOmega` Hence, reading of voltmeter
`=10/2=5V`


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