1.

Iron exhibits bcc structure at room temperature . Above 900^@C , it transforms to fcc structure. The ratio of the density of iron at room temperature to that at 900^@C(assuming molar mass and atomic radii of iron remain constant with temperature ) is

Answer»

`sqrt3/sqrt2`
`(4sqrt3)/(3sqrt2)`
`(3sqrt3)/(4sqrt2)`
`1/2`

Solution :Density `(RHO)=(ZxxM)/(a^3xxN_0)`
As M and a REMAIN contant and `N_0` is ALSO CONSTANT , `rho prop Z`
`rho_"bcc"/rho_"FCC"=Z_"bcc"/Z_"fcc"=2/4=1/2`


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