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Iron exhibits bcc structure at room temperature . Above 900^@C , it transforms to fcc structure. The ratio of the density of iron at room temperature to that at 900^@C(assuming molar mass and atomic radii of iron remain constant with temperature ) is |
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Answer» `sqrt3/sqrt2` As M and a REMAIN contant and `N_0` is ALSO CONSTANT , `rho prop Z` `rho_"bcc"/rho_"FCC"=Z_"bcc"/Z_"fcc"=2/4=1/2` |
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