Iron has a body centred cubic unit cell with a cell edge of 286.65 pm.The density of iron is 7.87 "gcm"^(-3). Use this information to calculate Avogadro's number (At. Mass of Fe =56 "g mol"^(-1))

Iron has a body centred cubic unit cell with a cell edge of 286.65 pm.

1.	Iron has a body centred cubic unit cell with a cell edge of 286.65 pm.The density of iron is 7.87 "gcm"^(-3). Use this information to calculate Avogadro's number (At. Mass of Fe =56 "g mol"^(-1))
Answer» Solution :For BCC unit cell of the ELEMENT Fe, Z=2 `N_0=(ZxxM)/(a^3xxrho)=(2xx56 G mol^(-1))/((286.65xx10^(-10)cm)^3xx(7.87 g cm^(-3)))=6.04xx10^23 mol^(-1)`