Iron has body centred cubic unit cell with a cell edge of 268.65 pm. The density of iron is7.87 " g cm"^(-3) . Use this information to calculate Avogadro's numer (At mass of Fe =56 "g mol"^(-1))

Iron has body centred cubic unit cell with a cell edge of 268.65 pm. T

1.	Iron has body centred cubic unit cell with a cell edge of 268.65 pm. The density of iron is7.87 " g cm"^(-3) . Use this information to calculate Avogadro's numer (At mass of Fe =56 "g mol"^(-1))
Answer» <P> Solution : For BCC unit cell of the element Fe, Z =2 ` N_(0)= ( Z xxM)/(a^(3) xx p) = ( 2xx 56 " MOL"^(-1))/(( 286.65 xx10^(-10) "cm")^(3) xx ( 7.87 " g cm" ^(-3)) ) = 6.04 xx 10^(23) " mol" ^(-1)`