Iron (II) oxide has a cubic structure and each unit cell has side 5Å. If the density of the oxide is 4 g cm^(-3), the number of oxide ions present in each unit cell is ("Molar mass of " FeO = 72 g " mol "^(-1),N_(A) = 6.02times10^(23)"mol^(-1))

Iron (II) oxide has a cubic structure and each unit cell has side 5Å.

1.	Iron (II) oxide has a cubic structure and each unit cell has side 5Å. If the density of the oxide is 4 g cm^(-3), the number of oxide ions present in each unit cell is ("Molar mass of " FeO = 72 g " mol "^(-1),N_(A) = 6.02times10^(23)"mol^(-1))
Answer» SOLUTION :`z=(rhotimesa^(3)timesNo)/M` `=((4" g "CM^(-3))(5times10^(-8))(6.02times10^(23)"mol"^(-1)))/(72" g "mol^(-1))` =4