1.

____ is strength in %W/V of 40 volume containing H_2O_2 solution.

Answer»

SOLUTION :`{:(2H_2O_2 to , 2H_2O+ O_2),("68gm","volume at 1 MOL STP =22.4 litre"):}`
1 mol `O_2` at STP = 1 mol `H_2O_2`
`therefore` 22.4 litre `O_2` from 68 gm of `H_2O_2`
`therefore` 40 litre `O_2` x gm
`therefore 22.4/40 = 68/x`
`therefore x=(68xx40)/22.4`=121.42 gm/L `H_2O_2`
`therefore H_2O_2` %W/V = `121.42/10`=12.14


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