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____ is strength in %W/V of 40 volume containing H_2O_2 solution. |
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Answer» SOLUTION :`{:(2H_2O_2 to , 2H_2O+ O_2),("68gm","volume at 1 MOL STP =22.4 litre"):}` 1 mol `O_2` at STP = 1 mol `H_2O_2` `therefore` 22.4 litre `O_2` from 68 gm of `H_2O_2` `therefore` 40 litre `O_2` x gm `therefore 22.4/40 = 68/x` `therefore x=(68xx40)/22.4`=121.42 gm/L `H_2O_2` `therefore H_2O_2` %W/V = `121.42/10`=12.14 |
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