1.

Isotherms of carbon dioxide at various temperatures are repersented in figure. Answer the following questions based on this figures. (i) In which state will CO_(2) exist between the points a and b at temperature T_(1) ? (ii) At what point will CO_(2) start liquefyinh when temperature is T_(1) ? (iii) At what point will CO_(2) be completely liquefued when temperature is T_(2) ? (iv) Will condensation take place when the temperature is T_(3) ? (v) What portion of the isotherm at T_(1) represent liquid and gaseous CO_(2) at equilibrium ?

Answer»


SOLUTION :The average VELOCITY of a gas is given by
`BARU =sqrt((8RT)/(piM))`
In the present case, `baru =9.0xx10^4 " cm " s^(-1)`,
`R=8.314xx10^7 " erg " K^(-1) mol^(-1)`
`T=T_1 (?) and M=44`
`:. "" 9.0xx10^4=sqrt((8xx8.314xx10^7xxT_1)/(3.14xx44))`
HENCE, `T_1 = 1682.5 K`.
The most probable velocity is given by
`ALPHA = sqrt((2RT)/M)`
`:. "" 9.0xx10^4=sqrt((2xx8.314xx10^7xxT_2)/(44))`
Which gives `T_2 = 2143.3 K`.


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