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It costs ₹ 3300 to paint the inner curved surface of a cylindrical vessel 10m deep at the rate of ₹ 30 per m2. Find the(i) inner curved surface area of the vessel,(ii) inner radius of the base, and(iii) capacity of the vessel. |
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Answer» (i) We know that Cost of painting inner curved surface of the vessel = cost of painting per m2 × inner curved surface of vessel By substituting the values 3300 = 30 × Inner curved surface of vessel On further calculation Inner curved surface of vessel = 110 m2 (ii) Consider r as the inner radius of the base It is given that depth = 10m We know that Inner curved surface of vessel = 2 πrh By substituting the values 110 = 2 × (22/7) × r × 10 So we get r = (110 × 7)/ (2 × 22 × 10) r = 1.75m (iii) We know that Capacity of the vessel = πr2h By substituting the values Capacity of the vessel = (22/7) × (1.75)2 × 10 So we get Capacity of the vessel = 96.25 m3 |
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