1.

It has been found that the pH of a 0.01 M solution of an organic acid is 4.15. Calculate the concentrationof the anion, the ionizationconstant of the acid and its pK_a.

Answer»

Solution :Calculationof `H^+` :pH=-LOG `[H^+]`= -4.15 = `bar5.85`
`therefore [H^+]`= Antilog `(bar5.85)=7.079xx10^(-5)`
Calculation of ionization constant `K_a` :
`{:("WEAK acid :",HA hArr, H^(+)+,A^-),("Initial M:",0.01,0,0),("EQUILIBRIUM M:",(0.01-x), x,x):}`
So, `[H^+]=[A^-]=7.079xx10^(-5)=x`
[HA]=(0.01 -x) `APPROX` 0.01 (because `0.01 GT gt gt x`) `K_a`
`=([H^+][A^-])/([HA])`
`=((7.079xx10^(-5))(7.079xx10^(-5)))/0.01`
`=5.011xx10^(-7)`
Calculation of `pK_a` :
`pK_a=-log K_a`
`=-log (5.011xx10^(-7))`
=-(0.6999-7)=-(-6.30)=+6.30


Discussion

No Comment Found